| Code | Factor 1 | Factor 2 | Result Field | Indicators | ||
|---|---|---|---|---|---|---|
| TESTB | Bit numbers | Character field | OF | ON | EQ | |
The TESTB operation compares the bits identified in factor 2 with the corresponding bits in the field named as the result field. The result field must be a one-position character field. Resulting indicators in positions 71 through 76 reflect the status of the result field bits. Factor 2 is always a source of bits for the result field.
Figure 1 illustrates uses of the TESTB operation.
For more information, see Bit Operations or Test Operations.
*...1....+....2....+....3....+....4....+....5....+....6....+....7...+....
CL0N01Factor1+++++++Opcode(E)+Factor2+++++++Result++++++++Len++D+HiLoEq....
*
* The field bit settings are FieldF = 00000001, and FieldG = 11110001.
*
* Indicator 16 is set on because bit 3 is off (0) in FieldF.
* Indicator 17 is set off.
C TESTB '3' FieldF 16 17
*
* Indicator 16 is set on because both bits 3 and 6 are off (0) in
* FieldF. Indicators 17 and 18 are set off.
C TESTB '36' FieldF 161718
*
* Indicator 17 is set on because bit 3 is off (0) and bit 7 is on
* (1) in FLDF. Indicators 16 and 18 are set off.
C TESTB '37' FieldF 161718
*
* Indicator 17 is set on because bit 7 is on (1) in FLDF.
* Indicator 16 is set off.
C TESTB '7' FieldF 16 17
*
* Indicator 17 is set on because bits 0,1,2, and 3 are off (0) and
* bit 7 is on (1). Indicators 16 and 18 are set off.
C TESTB FieldG FieldF 161718
*
* The hexadecimal literal X'88' (10001000) is used in factor 2.
* Indicator 17 is set on because at least one bit (bit 0) is on
* Indicators 16 and 18 are set off.
C TESTB X'88' FieldG 161718