示例

int funct(){ int exception = 2; if(exception){ throw exception; } return 0; } int main() { try { funct(); } catch (int ex) { cout << ex; }     return 0; }

解决方案

捕捉对异常的引用。 int funct(){ int exception = 2; if(exception){ throw exception; } return 0; } int main() { try { funct(); } catch (int &ex) { cout << ex; }     return 0; }