範例

int getNum(){
return 5;
}

void main( int argc, char* argv[]) {
while( a = getNum() ) {
cout << "A is still 5";
}
}

解決方案

如果指派是一項錯誤，請將它改成比較。否則，請在條件式陳述式之外進行指派。

int getNum(){
return 5;
}

void main( int argc, char* argv[]) {
int a = 5;
while( a == getNum() ) {
cout << "A is still 5";
}
}