Example

class MyClass {
public:
MyClass(int param, int param2=0);
operator double() const;
bool operator==(const MyClass& left, const MyClass& right);
private:
double num;
};

int main(int argc, char* argv[]){
MyClass a;
int b[] = {0,1,2};
for(int i=0; i<3; i++)
if( a == b[i] ){
//b[i] implicitly converted to MyClass
}
}
}

Solution

For single argument constructors (that are not copy constructors) or constructors that the compiler may use for conversion, declare the constructor as explicit. Instead of using implicit type conversion operators that the compiler may use unexpectedly, use custom methods explicitly.

class MyClass {
public:
explicit MyClass(int param, int param2=0);
double toDouble() const;
bool operator==(const MyClass& left, const MyClass& right);
private:
double num;
};

int main(int argc, char* argv[]){
MyClass a;
int b[] = {0,1,2};
for(int i=0; i<3; i++)
if( a.toDouble() == b[i] ){
//a explicitly converted to double
}
}
}