예제

int main(int argc, char* argv[]) { if(argc == 2){ goto END; }        cout << "argc  was not 2.. "; END: cout << "done"; return 0; }

솔루션

goto 문을 사용하지 마십시오. int main(int argc, char* argv[]) { if(argc == 2){ cout << "done"; } else{     cout << "argc  was not 2.. "; } return 0; }