範例

int main(int argc, char* argv[]) { if(argc != 2){ cout << "argc  was not 2.. "; }        END: cout << "done"; return 0; }

解決方案

可移除未用的標籤。 int main(int argc, char* argv[]) { if(argc != 2){ cout << "argc  was not 2.. "; }        cout << "done"; return 0; }